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NumberConversionUtil.java
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152 lines (142 loc) · 5.89 KB
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package org.json;
import java.math.BigDecimal;
import java.math.BigInteger;
class NumberConversionUtil {
/**
* Converts a string to a number using the narrowest possible type. Possible
* returns for this function are BigDecimal, Double, BigInteger, Long, and Integer.
* When a Double is returned, it should always be a valid Double and not NaN or +-infinity.
*
* @param input value to convert
* @return Number representation of the value.
* @throws NumberFormatException thrown if the value is not a valid number. A public
* caller should catch this and wrap it in a {@link JSONException} if applicable.
*/
static Number stringToNumber(final String input) throws NumberFormatException {
String val = input;
if (val.startsWith(".")){
val = "0"+val;
}
if (val.startsWith("-.")){
val = "-0."+val.substring(2);
}
char initial = val.charAt(0);
if ( isNumericChar(initial) || initial == '-' ) {
// decimal representation
if (isDecimalNotation(val)) {
// Use a BigDecimal all the time so we keep the original
// representation. BigDecimal doesn't support -0.0, ensure we
// keep that by forcing a decimal.
try {
BigDecimal bd = new BigDecimal(val);
if(initial == '-' && BigDecimal.ZERO.compareTo(bd)==0) {
return Double.valueOf(-0.0);
}
return bd;
} catch (NumberFormatException retryAsDouble) {
// this is to support "Hex Floats" like this: 0x1.0P-1074
try {
Double d = Double.valueOf(val);
if(d.isNaN() || d.isInfinite()) {
throw new NumberFormatException("val ["+input+"] is not a valid number.");
}
return d;
} catch (NumberFormatException ignore) {
throw new NumberFormatException("val ["+input+"] is not a valid number.");
}
}
}
val = removeLeadingZerosOfNumber(input);
initial = val.charAt(0);
if(initial == '0' && val.length() > 1) {
char at1 = val.charAt(1);
if(isNumericChar(at1)) {
throw new NumberFormatException("val ["+input+"] is not a valid number.");
}
} else if (initial == '-' && val.length() > 2) {
char at1 = val.charAt(1);
char at2 = val.charAt(2);
if(at1 == '0' && isNumericChar(at2)) {
throw new NumberFormatException("val ["+input+"] is not a valid number.");
}
}
// integer representation.
// This will narrow any values to the smallest reasonable Object representation
// (Integer, Long, or BigInteger)
// BigInteger down conversion: We use a similar bitLength compare as
// BigInteger#intValueExact uses. Increases GC, but objects hold
// only what they need. i.e. Less runtime overhead if the value is
// long lived.
BigInteger bi = new BigInteger(val);
if(bi.bitLength() <= 31){
return Integer.valueOf(bi.intValue());
}
if(bi.bitLength() <= 63){
return Long.valueOf(bi.longValue());
}
return bi;
}
throw new NumberFormatException("val ["+input+"] is not a valid number.");
}
/**
* Checks if the character is a numeric digit ('0' to '9').
*
* @param c The character to be checked.
* @return true if the character is a numeric digit, false otherwise.
*/
private static boolean isNumericChar(char c) {
return (c <= '9' && c >= '0');
}
/**
* Checks if the value could be considered a number in decimal number system.
* @param value
* @return
*/
static boolean potentialNumber(String value){
if (value == null || value.isEmpty()){
return false;
}
return potentialPositiveNumberStartingAtIndex(value, (value.charAt(0)=='-'?1:0));
}
/**
* Tests if the value should be tried as a decimal. It makes no test if there are actual digits.
*
* @param val value to test
* @return true if the string is "-0" or if it contains '.', 'e', or 'E', false otherwise.
*/
private static boolean isDecimalNotation(final String val) {
return val.indexOf('.') > -1 || val.indexOf('e') > -1
|| val.indexOf('E') > -1 || "-0".equals(val);
}
private static boolean potentialPositiveNumberStartingAtIndex(String value,int index){
if (index >= value.length()){
return false;
}
return digitAtIndex(value, (value.charAt(index)=='.'?index+1:index));
}
private static boolean digitAtIndex(String value, int index){
if (index >= value.length()){
return false;
}
return value.charAt(index) >= '0' && value.charAt(index) <= '9';
}
/**
* For a prospective number, remove the leading zeros
* @param value prospective number
* @return number without leading zeros
*/
private static String removeLeadingZerosOfNumber(String value){
if (value.equals("-")){return value;}
boolean negativeFirstChar = (value.charAt(0) == '-');
int counter = negativeFirstChar ? 1:0;
while (counter < value.length()){
if (value.charAt(counter) != '0'){
if (negativeFirstChar) {return "-".concat(value.substring(counter));}
return value.substring(counter);
}
++counter;
}
if (negativeFirstChar) {return "-0";}
return "0";
}
}